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A105806
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Triangle of number of partitions of n with nonnegative Dyson rank r=0,1,...,n-1.
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16
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1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 2, 1, 1, 0, 1, 3, 1, 2, 1, 1, 0, 1, 2, 3, 2, 2, 1, 1, 0, 1, 4, 3, 3, 2, 2, 1, 1, 0, 1, 4, 5, 3, 4, 2, 2, 1, 1, 0, 1, 6, 5, 6, 3, 4, 2, 2, 1, 1, 0, 1, 7, 8, 6, 6, 4, 4, 2, 2, 1, 1, 0, 1, 11, 8, 9, 7, 6, 4, 4, 2, 2, 1, 1, 0, 1, 11, 13, 10, 10, 7, 7, 4, 4, 2, 2, 1, 1, 0, 1
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OFFSET
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1,17
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COMMENTS
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The array with all ranks (including negative ones) is A063995.
a(n,-r)=a(n,r) for negative rank -r with r from 1,2,...,n-1 (due to conjugation of partitions of n; see the link).
Dyson's rank of a partition of n is the maximal part minus the number of parts, i.e. the number of columns minus the number of rows of the Ferrers diagram (see the link) of the partition.
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LINKS
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FORMULA
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a(n, r)= number of partitions of n with rank r, with r from 0, 1, ..., n-1.
G.f. of column r: (1/Product_{k>=1} (1-x^k)) * Sum_{k>=1} (-1)^(k-1) * x^(r*k) * ( x^(k*(3*k-1)/2) - x^(k*(3*k+1)/2) ). - Seiichi Manyama, May 21 2023
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EXAMPLE
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Triangle starts:
1;
0, 1;
1, 0, 1;
1, 1, 0, 1;
1, 1, 1, 0, 1;
1, 2, 1, 1, 0, 1; ...
Row 6, second entry is 2 because there are 2 partitions of n=6 with rank r=2-1=1, namely (3^2) and (1^2,4).
The table of p(n,m) = number of partitions of n with rank m, taken from Dyson (1969):
n\m -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
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0 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
1 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0,
2 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0,
3 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0,
4 0, 0, 0, 1, 0, 1, 1, 1, 0, 1, 0, 0, 0,
5 0, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 0,
6 0, 1, 0, 1, 1, 2, 1, 2, 1, 1, 0, 1, 0,
7 1, 0, 1, 1, 2, 1, 3, 1, 2, 1, 1, 0, 1,
...
The central triangle is A063995, the right-hand triangle is the present sequence. - N. J. A. Sloane, Jan 23 2020
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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