OFFSET
2,1
COMMENTS
Smallest integer divisible by Fibonacci(2n) such that the continued fraction expansion of a(n)/phi has period 2 or 4.
FORMULA
a(n) = Fibonacci(2n)*ceiling(Lucas(2n)/2).
Fibonacci(2n)*(A071618(n)+1). - Thomas Baruchel, Nov 26 2003
Empirical g.f.: -2*x^2*(x^7 - 7*x^6 - 17*x^4 + 131*x^3 - 6*x^2 + 6*x - 6) / ((x^2 - 7*x + 1)*(x^2 - 3*x + 1)*(x^4 + 3*x^3 + 8*x^2 + 3*x + 1)). - Colin Barker, Jan 11 2014
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Thomas Baruchel, Sep 21 2003
STATUS
approved