OFFSET
1,2
LINKS
FORMULA
If n>1 then a(n) = (2*10^n + 10)/15. - Robert Gerbicz, Sep 06 2002
a(n) = A073550(n) for n >= 3. - Georg Fischer, Oct 13 2022
From Elmo R. Oliveira, Jul 22 2025: (Start)
G.f.: 2*x^2*(7 - 10*x)/((1-x)*(1-10*x)).
E.g.f.: 2*(-6 - 15*x + 5*exp(x) + exp(10*x))/15.
a(n) = 2*A067275(n) for n >= 2.
a(n) = 11*a(n-1) - 10*a(n-2) for n > 3. (End)
EXAMPLE
a(2) = 14 because there are 14 Fibonacci numbers up to 10^2 which end in 7.
MATHEMATICA
Join[{0}, Table[10 FromDigits[PadRight[{1}, n, 3]]+4, {n, 30}]] (* Harvey P. Dale, Mar 29 2023 *)
CROSSREFS
KEYWORD
base,nonn,easy
AUTHOR
Shyam Sunder Gupta, Aug 15 2002
EXTENSIONS
More terms from Robert Gerbicz, Sep 06 2002
STATUS
approved
