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A057246
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s=0; d is divisor of n [here d <= n/d]; if gcd(d,n/d)=1 or gcd(d,n/d)=d then s=s+d+(n/d); [if d=n/d then s=s+d]: The sequence contains composite n for which s = 2*n.
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0
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OFFSET
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1,1
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COMMENTS
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LINKS
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EXAMPLE
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a(2)=28, gcd(1,28)=gcd(4,28/4)=1, gcd(2,28/2)=2, 1+28+4+7+2+14=56. 56-28=28.
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MATHEMATICA
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f[ n_Integer ] := (ds = Divisors[ n ]; sq = N[ Sqrt[ n ] ]; l = 1; While[ ds[[ l ] ] <= sq, l++ ]; l = l - 1; ds = Take[ ds, l ]; s = 1; k = 2; While[ k <= l, If[ GCD[ ds[[ k ] ], n/ds[[ k ] ] ] == 1 || GCD[ ds[[ k ] ], n/ds[[ k ] ] ] == ds[[ k ] ], s = s + ds[[ k ] ] + n/ds[[ k ] ] ]; k++ ]; If[ ds[[ -1 ] ] == n/ds[[ -1 ] ], s = s - d ]; s) Do[ If[ ! PrimeQ[ n ] && f[ n ] == n, Print[ n ] ], {n, 2, 33429000} ] (* Robert G. Wilson v, Nov 09 2000 *)
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PROG
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(PARI) is(n)=my(s, g); fordiv(n, d, if(d^2<n&&((g=gcd(d, n/d))==1||g==d), s+=d+n/d)); g=sqrtint(n); if(n==g^2, s+=g); s==n+n \\ Charles R Greathouse IV, Oct 23 2011
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CROSSREFS
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KEYWORD
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more,nonn
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AUTHOR
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STATUS
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approved
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