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A055573
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Number of terms in simple continued fraction for n-th harmonic number H_n = Sum_{k=1..n} (1/k).
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24
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1, 2, 3, 2, 5, 4, 6, 7, 10, 8, 7, 10, 15, 9, 9, 17, 18, 11, 20, 16, 18, 18, 23, 19, 24, 25, 24, 26, 29, 21, 24, 23, 26, 25, 32, 34, 33, 26, 24, 31, 32, 31, 36, 36, 39, 32, 34, 42, 47, 44, 46, 35, 40, 48, 43, 47, 59, 50, 49, 39, 50, 66, 54, 44, 54, 49, 41, 64, 47, 46, 54, 71, 72
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OFFSET
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1,2
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COMMENTS
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By "simple continued fraction" is meant a continued fraction whose terms are positive integers and the final term is >= 2.
Does any number appear infinitely often in this sequence?
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REFERENCES
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S. R. Finch, Mathematical Constants, Cambridge, 2003, pp. 156
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LINKS
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FORMULA
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It appears that lim n -> infinity a(n)/n = C = 0.84... - Benoit Cloitre, May 04 2002
Conjecture: limit n -> infinity a(n)/n = 12*log(2)/Pi^2 = 0.84..... = A089729 Levy's constant. - Benoit Cloitre, Jan 17 2004
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EXAMPLE
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Sum_{k=1 to 3} [1/k] = 11/6 = 1 + 1/(1 + 1/5), so the 3rd term is 3 because the simple continued fraction for the 3rd harmonic number has 3 terms.
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MATHEMATICA
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Table[ Length[ ContinuedFraction[ HarmonicNumber[n]]], {n, 1, 75}] (* Robert G. Wilson v, Dec 22 2003 *)
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PROG
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(PARI) c=0; h=0; for(n=1, 500, write("projects/b055573.txt", c++, " ", #contfrac(h+=1/n))) \\ M. F. Hasler, May 31 2008
(Python)
from sympy import harmonic
from sympy.ntheory.continued_fraction import continued_fraction
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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