

A058027


Sum of terms of continued fraction for nth harmonic number, 1 + 1/2 + 1/3 + ... + 1/n.


9



1, 3, 7, 14, 15, 10, 16, 19, 26, 35, 72, 41, 38, 79, 83, 42, 59, 143, 68, 61, 70, 51, 50, 78, 74, 82, 130, 113, 111, 315, 235, 1190, 211, 407, 112, 122, 142, 246, 693, 133, 138, 162, 1904, 243, 170, 539, 363, 210, 197, 518, 275, 502, 527, 316, 1729, 224, 228, 909
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OFFSET

1,2


COMMENTS

Is anything known about the asymptotics of this sequence?
Should be asymptotic to D*n^(3/2) with D=0.4....  Benoit Cloitre, Dec 23 2003


LINKS

G. C. Greubel, Table of n, a(n) for n = 1..1000
Eric Weisstein's World of Mathematics, Harmonic Number
Eric Weisstein's World of Mathematics, Continued Fraction


EXAMPLE

1 + 1/2 +1/3 = 11/6 = 1 + 1/(1 + 1/5). So sum of terms of continued fraction is 1 + 1 + 5 = 7.


MATHEMATICA

Table[Plus @@ ContinuedFraction[HarmonicNumber[n]], {n, 60}] (* Ray Chandler, Sep 17 2005 *)


PROG

(PARI) a(n) = vecsum(contfrac(sum(k=1, n, 1/k))); \\ Michel Marcus, Mar 23 2017


CROSSREFS

mth harmonic number H(m) = A001008(m)/A002805(m).
Cf. A055573, A100398, A110020, A112286, A112287.
Sequence in context: A172291 A089305 A112618 * A128661 A175339 A009461
Adjacent sequences: A058024 A058025 A058026 * A058028 A058029 A058030


KEYWORD

easy,nonn


AUTHOR

Leroy Quet, Nov 15 2000


STATUS

approved



