|
|
A022900
|
|
Number of solutions to c(1)*prime(3) + ... + c(n)*prime(n+2) = 0, where c(i) = +-1 for i>1, c(1) = 1.
|
|
3
|
|
|
0, 0, 0, 1, 0, 1, 0, 1, 0, 8, 0, 22, 0, 42, 0, 147, 0, 663, 0, 1803, 0, 7410, 0, 22463, 0, 87397, 0, 291211, 0, 1091736, 0, 3896012, 0, 13992225, 0, 49681944, 0, 184771042, 0, 677854904, 0, 2495656379, 0, 9260633829, 0, 34281074654, 0, 127420198855, 0
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,10
|
|
LINKS
|
|
|
FORMULA
|
a(n) = [x^5] Product_{k=4..n+2} (x^prime(k) + 1/x^prime(k)). - Ilya Gutkovskiy, Jan 28 2024
|
|
EXAMPLE
|
a(8) counts the unique solution {5, -7, 11, -13, 17, -19, -23, 29}.
|
|
MATHEMATICA
|
{f, s} = {3, 0}; Table[t = Map[Prime[# + f - 1] &, Range[2, z]]; Count[Map[Apply[Plus, #] &, Map[t # &, Tuples[{-1, 1}, Length[t]]]], s - Prime[f]], {z, 22}]
(* A022900, a(n) = number of solutions of "sum = s" using Prime(f) to Prime(f+n-1) *)
n = 8; t = Map[Prime[# + f - 1] &, Range[n]]; Map[#[[2]] &, Select[Map[{Apply[Plus, #], #} &, Map[t # &, Map[Prepend[#, 1] &, Tuples[{-1, 1}, Length[t] - 1]]]], #[[1]] == s &]] (* the unique solution of using n=8 primes; Peter J. C. Moses, Oct 01 2013 *)
|
|
PROG
|
(PARI) A022900(n, rhs=0, firstprime=3)={rhs-=prime(firstprime); my(p=vector(n-1, i, prime(i+firstprime))); sum(i=1, 2^(n-1), sum(j=1, #p, (1-bittest(i, j-1)<<1)*p[j])==rhs)} \\ For illustrative purpose, too slow for n >> 20. - M. F. Hasler, Aug 08 2015
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|