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A022168
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Triangle of Gaussian binomial coefficients [ n,k ] for q = 4.
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25
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1, 1, 1, 1, 5, 1, 1, 21, 21, 1, 1, 85, 357, 85, 1, 1, 341, 5797, 5797, 341, 1, 1, 1365, 93093, 376805, 93093, 1365, 1, 1, 5461, 1490853, 24208613, 24208613, 1490853, 5461, 1, 1, 21845, 23859109, 1550842085, 6221613541
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OFFSET
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0,5
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COMMENTS
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The coefficients of the matrix inverse are apparently given by T^(-1)(n,k) = (-1)^n*A157784(n,k). - R. J. Mathar, Mar 12 2013
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REFERENCES
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F. J. MacWilliams and N. J. A. Sloane, The Theory of Error-Correcting Codes, Elsevier-North Holland, 1978, p. 698.
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LINKS
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FORMULA
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EXAMPLE
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1;
1, 1;
1, 5, 1;
1, 21, 21, 1;
1, 85, 357, 85, 1;
1, 341, 5797, 5797, 341, 1;
1, 1365, 93093, 376805, 93093, 1365, 1;
1, 5461, 1490853, 24208613, 24208613, 1490853, 5461, 1;
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MAPLE
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MATHEMATICA
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gaussianBinom[n_, k_, q_] := Product[q^i - 1, {i, n}]/Product[q^j - 1, {j, n - k}]/Product[q^l - 1, {l, k}]; Column[Table[gaussianBinom[n, k, 4], {n, 0, 8}, {k, 0, n}], Center] (* Alonso del Arte, Nov 14 2011 *)
Table[QBinomial[n, k, 4], {n, 0, 10}, {k, 0, n}]//Flatten (* or *) q:= 4; T[n_, 0]:= 1; T[n_, n_]:= 1; T[n_, k_]:= T[n, k] = If[k < 0 || n < k, 0, T[n-1, k -1] +q^k*T[n-1, k]]; Table[T[n, k], {n, 0, 10}, {k, 0, n}] // Flatten (* G. C. Greubel, May 27 2018 *)
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PROG
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(PARI) {q=4; T(n, k) = if(k==0, 1, if (k==n, 1, if (k<0 || n<k, 0, T(n-1, k-1) + q^k*T(n-1, k))))};
for(n=0, 10, for(k=0, n, print1(T(n, k), ", "))) \\ G. C. Greubel, May 27 2018
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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