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 A006022 Sprague-Grundy (or Nim) values for the game of Maundy cake on an n X 1 sheet. (Formerly M2219) 12
 0, 1, 1, 3, 1, 4, 1, 7, 4, 6, 1, 10, 1, 8, 6, 15, 1, 13, 1, 16, 8, 12, 1, 22, 6, 14, 13, 22, 1, 21, 1, 31, 12, 18, 8, 31, 1, 20, 14, 36, 1, 29, 1, 34, 21, 24, 1, 46, 8, 31, 18, 40, 1, 40, 12, 50, 20, 30, 1, 51, 1, 32, 29, 63, 14, 45, 1, 52, 24, 43, 1, 67, 1, 38, 31, 58, 12, 53, 1 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,4 COMMENTS There are three equivalent formulas for a(n). Suppose n >= 2, and let p1 <= p2 <= ... <= pk be the prime factors of n, with repetition. Theorem 1: a(1) = 0. For n >= 2, a(n) = n*s(n), where s(n) = 1/p1 + 1/(p1*p2) + 1/(p1*p2*p3) + ... + 1/(p1*p2*...*pk). This is implicit in Berlekamp, Conway and Guy, Winning Ways, 2 vols., 1982, pp. 28, 53. Note that s(n) = A322034(n) / A322035(n). David James Sycamore observed on Nov 24 2018 that Theorem 1 implies a(n) < n for all n (see comments in A322034), and also leads to a simple recurrence for a(n): Theorem 2: a(1) = 0. For n >= 2, a(n) = p*a(n/p) + 1, where p is the largest prime factor of n. Proof. (Th. 1 implies Th. 2) If n is a prime, Theorem 1 gives a(n) = 1 = n*a(1)+1. For a nonprime n, let n = m*p where p is the largest prime factor of n and m >= 2. From Theorem 1, a(m) = m*s(m), a(n) = q*m*(s(m) + 1/n) = q*a(m) + 1. (Th. 2 implies Th. 1) The reverse implication is equally easy. Theorem 2 is equivalent to the following more complicated recurrence: Theorem 3: a(1) = 0. For n >= 2, a(n) = max_{p|n, p prime} (p*a(n/p)+1). REFERENCES E. R. Berlekamp, J. H. Conway and R. K. Guy, Winning Ways, Academic Press, NY, 2 vols., 1982, see p. 28, 53. E. R. Berlekamp, J. H. Conway and R. K. Guy, Winning Ways, Second Edition, Vol. 1, A K Peters, 2001, pp. 27, 51. N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence). LINKS Reinhard Zumkeller, Table of n, a(n) for n = 1..10000 Jonathan Blanchette, Robert LaganiÃ¨re, A Curious Link Between Prime Numbers, the Maundy Cake Problem and Parallel Sorting, arXiv:1910.11749 [cs.DS], 2019. FORMULA a(n) = n * Sum_{k=1..N} (1/(p1^m1*p2^m2*...*pk^mk)) * (pk^mk-1)/(pk-1) for n>=2, where pk is the k-th distinct prime factor of n, N is the number of distinct prime factors of n, and mk is the multiplicity of pk occurring in n. To prove this, expand the factors in Theorem 1 and use the geometrical series identity. - Jonathan Blanchette, Nov 01 2019 From Antti Karttunen, Apr 12 2020: (Start) a(n) = A322382(n) + A333791(n). a(n) = A332993(n) - n = A001065(n) - A333783(n). (End) EXAMPLE For n=24, s(24) = 1/2 + 1/4 + 1/8 + 1/24 = 11/12, so a(24) = 24*11/12 = 22. MAPLE P:=proc(n) local FM: FM:=ifactors(n)[2]: seq(seq(FM[j][1], k=1..FM[j][2]), j=1..nops(FM)) end: # A027746 s:=proc(n) local i, t, b; global P; t:=0; b:=1; for i in [P(n)] do b:=b*i; t:=t+1/b; od; t; end; # A322034/A0322035 A006022 := n -> if n = 1 then 0 else n*s(n); fi; # N. J. A. Sloane, Nov 28 2018 MATHEMATICA Nest[Function[{a, n}, Append[a, Max@ Map[# a[[n/#]] + 1 &, Rest@ Divisors@ n]]] @@ {#, Length@ # + 1} &, {0, 1}, 77] (* Michael De Vlieger, Nov 23 2018 *) PROG (Haskell) a006022 1 = 0 a006022 n = (+ 1) \$ sum \$ takeWhile (> 1) \$           iterate (\x -> x `div` a020639 x) (a032742 n) -- Reinhard Zumkeller, Jun 03 2012 (PARI) lista(nn) = {my(v = vector(nn)); for (n=1, nn, if (n>1, my(m = 0); fordiv (n, d, if (d>1, m = max(m, d*v[n/d]+1))); v[n] = m; ); print1(v[n], ", "); ); } \\ Michel Marcus, Nov 25 2018 CROSSREFS Cf. A020639, A032742, A001348, A002182, A008864. Cf. also A027746, A306264, A306363, A322034, A322035, A322036, A322382, A328898, A333783, A332993, A333791. Row sums of A328969. Sequence in context: A295276 A301856 A301829 * A326065 A078896 A322582 Adjacent sequences:  A006019 A006020 A006021 * A006023 A006024 A006025 KEYWORD nonn AUTHOR EXTENSIONS Edited and extended by Christian G. Bower, Oct 18 2002 Entry revised by N. J. A. Sloane, Nov 28 2018 STATUS approved

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Last modified September 22 00:33 EDT 2020. Contains 337275 sequences. (Running on oeis4.)