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A003435
Number of directed Hamiltonian circuits on n-octahedron with a marked starting node.
(Formerly M4578)
3
8, 192, 11904, 1125120, 153262080, 28507207680, 6951513784320, 2153151603671040, 826060810479206400, 384600188992919961600, 213656089636192754073600, 139620366072628402087526400, 106033731334825319789808844800
OFFSET
2,1
COMMENTS
Also called the relaxed menage problem (cf. A000179).
These are labeled and the order and starting point matter.
REFERENCES
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
LINKS
Kenneth P. Bogart and Peter G. Doyle, Nonsexist solution of the menage problem, Amer. Math. Monthly 93 (1986), no. 7, 514-519.
D. Singmaster, Enumerating unlabeled Hamiltonian circuts, Preprint (1974).
D. Singmaster, Hamiltonian circuits on the n-dimensional octahedron, J. Combinatorial Theory Ser. B 19 (1975), no. 1, 1-4.
Eric Weisstein's World of Mathematics, Cocktail Party Graph
FORMULA
For n >= 2, a(n) = Sum_{k=0..n}(-1)^k*binomial(n, k)*((2*n)/(2*n-k))*2^k*(2*n-k)!.
Conjecture: a(n) -(4*n^2 - 2*n + 5)*a(n-1) + 2*(n-1)*(4*n-17)*a(n-2) + 12*(n-1)*(n-2)*a(n-3) = 0. - R. J. Mathar, Oct 02 2013
Recurrence: (2*n-3)*a(n) = 2*n*(4*n^2 - 8*n + 5)*a(n-1) + 4*(n-1)*n*(2*n-1)*a(n-2). - Vaclav Kotesovec, Feb 12 2014
a(n) ~ sqrt(Pi) * 2^(2*n+1) * n^(2*n+1/2) / exp(2*n+1). - Vaclav Kotesovec, Feb 12 2014
a(n) = -(-2)^(n+1)*n!*hypergeom([n, -n], [], 1/2). - Peter Luschny, Nov 10 2016
EXAMPLE
n=2: label vertices of a square 1,2,3,4. Then the 8 Hamiltonian circuits are 1234, 1432, 2341, 2143, 3412, 3214, 4123, 4321; so a(2) = 8.
MAPLE
A003435 := n->add((-1)^k*binomial(n, k)*((2*n)/(2*n-k))*2^k*(2*n-k)!, k=0..n);
MATHEMATICA
a[n_] := 2^n*n!*(2n-1)!!*Hypergeometric1F1[-n, 1-2n, -2]; Table[ a[n], {n, 2, 14}] (* Jean-François Alcover, Nov 04 2011 *)
PROG
(PARI) a(n)=sum(k=0, n, (-1)^k*binomial(n, k)*((2*n)/(2*n-k))*2^k*(2*n-k)!) \\ Charles R Greathouse IV, Nov 04 2011
(Magma) [(&+[ (-1)^k*2^(k+1)*n*Binomial(n, k)*Factorial(2*n-k-1): k in [0..n]]) : n in [2..20]]; // G. C. Greubel, Nov 17 2022
(SageMath) [sum( (-1)^k*2^(k+1)*n*binomial(n, k)*factorial(2*n-k-1) for k in (0..n)) for n in (2..20)] # G. C. Greubel, Nov 17 2022
CROSSREFS
KEYWORD
nonn,nice,easy
EXTENSIONS
Name made more precise by Andrew Howroyd, May 14 2017
STATUS
approved

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Last modified September 23 00:23 EDT 2024. Contains 376140 sequences. (Running on oeis4.)