OFFSET
1,36
COMMENTS
The number of steps to reach a term of A048103, when starting from n, and applying succesively the function A392879, which guarantees that on every step the value of A276085 stays invariant.
Positions of the first occurrence of n, for n>=0 are: 1, 4, 36, 22500, 2647102500, ..., which seems to suggest a factorization pattern 2^2 * Product_{i>=2} prime(i)^(prime(i)-1).
LINKS
EXAMPLE
For n = 27 = 3^3, A392879(27) = 5, thus a(27) = 1+a(5) = 1.
For n = 36 = 2^2 * 3^2, A392879(36) = 27, thus a(36) = 1+a(27) = 2.
For n = 823543 = 7^7, A392879(n) = 11 (which is one of the fixed points), thus a(823543) = 1.
For n = 367653125 = 5^5 * 7^6, A392879(n) = 7^7 = 823543, thus a(367653125) = 1+a(7^7) = 2.
For n = 6361161361558200394723968750000 [= A380459(5005)] = 2^4 * 3^4 * 5^9 * 7^13 * 11^10,
A392879(n) = 3578153265876487722032232421875 = 3^6 * 5^9 * 7^13 * 11^10,
A392879^2(n) = 122707587993020840947607421875 = 5^11 * 7^13 * 11^10,
A392879^3(n) = 615697593513781371538715 = 5^1 * 7^15 * 11^10,
A392879^4(n) = 109844993185235 = 5^1 * 7^1 * 11^12,
A392879^5(n) = 5005 = 5 * 7 * 11 * 13,
and as A392879(5005) = 5005, we have reached a fixed point in 5 steps, thus a(n) = 5.
PROG
CROSSREFS
KEYWORD
nonn
AUTHOR
Antti Karttunen, Jan 31 2026
STATUS
approved
