OFFSET
1,2
COMMENTS
The number of bi-unitary divisors of n^2 is A322327(n).
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..10000
FORMULA
a(n) = A188999(n^2).
Multiplicative with a(p^e) = (p^(2*e+1)-1)/(p-1) - p^e.
Dirichlet g.f.: zeta(s) * zeta(s-1) * zeta(s-2) * Product_{p prime} (1 - 1/p^(s-1) + 1/p^(2*s-3) - 1/p^(2*s-2) + 1/p^(2*s-1) - 1/p^(3*s-3)).
Sum_{k=1..n} a(k) ~ c * n^3 / 3, where c = zeta(2) * zeta(3) * Product_{p prime} (1 - 1/p^2 + 1/p^3 - 1/p^4 + 1/p^5 - 1/p^6) = 1.38365632653061275303... .
a(n) = sigma(n / rad(n)) * usigma(n * rad(n)), where sigma = A000203, usigma = A034448, rad = A007947. - Aloe Poliszuk, Nov 11 2025
MATHEMATICA
f[p_, e_] := (p^(2*e + 1) - 1)/(p - 1) - p^e; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100]
PROG
(PARI) a(n) = {my(f = factor(n)); prod(i = 1, #f~, (f[i, 1]^(2*f[i, 2] + 1) - 1)/(f[i, 1] - 1) - f[i, 1]^f[i, 2]); }
CROSSREFS
KEYWORD
nonn,mult,easy
AUTHOR
Amiram Eldar, Nov 10 2025
STATUS
approved
