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A387010
a(n) = Sum_{k=0..n} binomial(4*n+3,k).
7
1, 8, 67, 576, 5036, 44552, 397594, 3572224, 32267668, 292750368, 2665685155, 24347665728, 222972599812, 2046626681072, 18823260696452, 173427623923712, 1600383346290116, 14789063407109600, 136838247669241276, 1267571539176770816, 11754134090271100336
OFFSET
0,2
LINKS
FORMULA
a(n) = [x^n] (1+x)^(4*n+3)/(1-x).
a(n) = [x^n] 1/((1-x)^(3*n+3) * (1-2*x)).
a(n) = Sum_{k=0..n} 2^k * (-1)^(n-k) * binomial(4*n+3,k) * binomial(4*n-k+2,n-k).
a(n) = Sum_{k=0..n} 2^k * binomial(4*n-k+2,n-k).
G.f.: g^4/((2-g) * (4-3*g)) where g = 1+x*g^4 is the g.f. of A002293.
D-finite with recurrence: 128*(4*n-1)*(2*n-1)*(4*n-3)*(11*n^2+8*n+1)*a(n-2) -8*(946*n^5-434*n^4-518*n^3+143*n^2+46*n-3)*a(n-1) +3*n*(3*n+1)*(3*n+2)*(11*n^2-14*n+4)*a(n) = 0. - Georg Fischer, Aug 17 2025
a(n) ~ 2^(8*n + 11/2) / (sqrt(Pi*n) * 3^(3*n + 5/2)). - Vaclav Kotesovec, Oct 19 2025
a(n) = Sum_{k=0..floor(n/2)} binomial(4*n+4,n-2*k). - Seiichi Manyama, Nov 11 2025
MATHEMATICA
Table[Sum[Binomial[4*n+3, k], {k, 0, n}], {n, 0, 25}] (* Vincenzo Librandi, Aug 16 2025 *)
PROG
(PARI) a(n) = sum(k=0, n, binomial(4*n+3, k));
(Magma) [&+[Binomial(4*n+3, k): k in [0..n]]: n in [0..25]]; // Vincenzo Librandi, Aug 16 2025
KEYWORD
nonn
AUTHOR
Seiichi Manyama, Aug 12 2025
STATUS
approved