OFFSET
1,3
COMMENTS
Numbers k for which exists at least one solution to k = x^2 + (z^2 - x)^2 in integers x and z with x >= 0 and z >= sqrt(2*x).
Subsequence of A001481.
LINKS
Felix Huber, Table of n, a(n) for n = 1..10000
Wikipedia, Sum of two squares theorem
FORMULA
k = m^(4*j) is in the sequence for nonnegative integers m and j (not both 0) because x = 0 and z = m^j is a solution to m^(4*j) = x^2 + (z^2 - x)^2.
EXAMPLE
10 is in the sequence because 10 = 1^2 + 3^2 and 1 + 3 = 2^2.
81 is in the sequence because 81 = 0^2 + 9^2 and 0 + 9 = 3^2.
MAPLE
PROG
(PARI) isok(n)=my(x=0, r=0); while(x<=sqrt(n) && r==0, if(issquare(n-x^2) && issquare(x+sqrtint(n-x^2)), r=1); x++); r; \\ Michel Marcus, Feb 10 2025
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Felix Huber, Jan 25 2025
STATUS
approved
