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A379925
Numbers k for which nonnegative integers x and y exist such that x^2 + y^2 = k and x + y is a square.
1
0, 1, 8, 10, 16, 41, 45, 53, 65, 81, 128, 130, 136, 146, 160, 178, 200, 226, 256, 313, 317, 325, 337, 353, 373, 397, 425, 457, 493, 533, 577, 625, 648, 650, 656, 666, 680, 698, 720, 746, 776, 810, 848, 890, 936, 986, 1040, 1098, 1160, 1201, 1205, 1213, 1225, 1226
OFFSET
1,3
COMMENTS
Numbers k for which exists at least one solution to k = x^2 + (z^2 - x)^2 in integers x and z with x >= 0 and z >= sqrt(2*x).
Subsequence of A001481.
FORMULA
k = m^(4*j) is in the sequence for nonnegative integers m and j (not both 0) because x = 0 and z = m^j is a solution to m^(4*j) = x^2 + (z^2 - x)^2.
EXAMPLE
10 is in the sequence because 10 = 1^2 + 3^2 and 1 + 3 = 2^2.
81 is in the sequence because 81 = 0^2 + 9^2 and 0 + 9 = 3^2.
MAPLE
# Calculates the first 10005 terms.
A379925:=proc(K)
local i, j, L;
L:={};
for i from 0 to floor(sqrt((K+1)^2)/2) do
for j from 0 to floor(sqrt((K+1)^2/2-i^2)) do
if issqr(i+j) then
L:=L union {i^2+j^2}
fi
od
od;
return op(L)
end proc;
A379925(1737);
PROG
(PARI) isok(n)=my(x=0, r=0); while(x<=sqrt(n) && r==0, if(issquare(n-x^2) && issquare(x+sqrtint(n-x^2)), r=1); x++); r; \\ Michel Marcus, Feb 10 2025
KEYWORD
easy,nonn
AUTHOR
Felix Huber, Jan 25 2025
STATUS
approved