login
A379490
Odd squares s such that 2*s is equal to bitwise-AND of 2*s and sigma(s).
3
399736269009, 1013616036225, 1393148751631700625, 2998748839068013955625, 3547850289210724050225
OFFSET
1,1
COMMENTS
If there are any quasiperfect numbers, i.e., numbers x for which sigma(x) = 2*x+1, then they should occur also in this sequence.
Square roots of these terms are: 632247, 1006785, 1180317225, 54760833075, 59563833735.
Question: Are there any solutions to similar equations "Odd squares s such that 2*s is equal to bitwise-AND of 2*s and A001065(s)" and "Odd squares s such that 3*s is equal to bitwise-AND of 3*s and sigma(s)"? Such sequences would contain odd triperfect numbers, if they exist (cf. A005820, A347391, A347884). - Antti Karttunen, Aug 19 2025
a(6) > 4*10^21. - Giovanni Resta, Aug 19 2025
LINKS
Paolo Cattaneo, Sui numeri quasiperfetti, Bollettino dell’Unione Matematica Italiana, Serie 3, Vol.6(1951), n.1, p. 59-62.
P. Hagis and G. L. Cohen, Some Results Concerning Quasiperfect Numbers, J. Austral. Math. Soc. Ser. A 33, 275-286, 1982.
V. Siva Rama Prasad and C. Sunitha, On quasiperfect numbers, Notes on Number Theory and Discrete Mathematics, Vol. 23, 2017, No. 3, 73-78.
PROG
(PARI) k=0; forstep(n=1, oo, 2, if(!((n-1)%(2^27)), print1("("n")")); if(!isprime(n) && omega(n)>=3, f = factor(n); sq=n^2; sig=prod(i=1, #f~, ((f[i, 1]^(1+(2*f[i, 2])))-1) / (f[i, 1]-1)); if(((2*sq)==bitand(2*sq, sig)), k++; print1(sq, ", "))));
CROSSREFS
Odd squares in A324647.
Intersection of A016754 and A324647.
Subsequence of A325311, which is a subsequence of A005231.
Cf. also A336700, A336701, A337339, A337342, A348742, A379474, A379503, A379505, A379949 for other conditions that quasiperfect numbers should satisfy.
Sequence in context: A080122 A269417 A281963 * A387154 A357687 A363799
KEYWORD
nonn,more
AUTHOR
Antti Karttunen, Jan 13 2025
EXTENSIONS
a(4) and a(5) from Giovanni Resta, Aug 19 2025
STATUS
approved