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A377517
The sum of the divisors of n that are terms in A276078.
5
1, 3, 4, 3, 6, 12, 8, 3, 13, 18, 12, 12, 14, 24, 24, 3, 18, 39, 20, 18, 32, 36, 24, 12, 31, 42, 13, 24, 30, 72, 32, 3, 48, 54, 48, 39, 38, 60, 56, 18, 42, 96, 44, 36, 78, 72, 48, 12, 57, 93, 72, 42, 54, 39, 72, 24, 80, 90, 60, 72, 62, 96, 104, 3, 84, 144, 68, 54
OFFSET
1,2
COMMENTS
First differs from A046897 at n = 27 = 3^3: a(27) = 13, while A046897(27) = 40.
The number of these divisors is A377516(n), and the largest of them is A377515(n).
LINKS
FORMULA
a(n) = A000203(A377515(n)).
Multiplicative with a(p^e) = (p^(min(pi(p), e)+1) - 1)/(p - 1), where pi(n) = A000720(n).
Dirichlet g.f.: zeta(s-1) * zeta(s) * Product_{p prime} (p^((pi(p)+1)*s) - p^(pi(p)+1))/p^((pi(p)+1)*s).
Sum_{k=1..n} a(k) ~ c * n^2 / 2, where c = zeta(2) * Product_{p prime} (1 - 1/p^(pi(p)+1)) = 1.18603586369737251334... .
MATHEMATICA
f[p_, e_] := (p^(Min[PrimePi[p], e] + 1) - 1)/(p-1); a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100]
PROG
(PARI) a(n) = {my(f = factor(n)); prod(i = 1, #f~, (f[i, 1]^(min(primepi(f[i, 1]), f[i, 2]) + 1) - 1)/(f[i, 1] - 1)); }
KEYWORD
nonn,easy,mult
AUTHOR
Amiram Eldar, Oct 30 2024
STATUS
approved