OFFSET
0,2
COMMENTS
The sequence of Apéry numbers A005258 defined by A005258(n) = Sum_{k = 0..n} binomial(n, k)^2*binomial(n+k, k) satisfies the pair of supercongruences
1) A005258(n*p^r) == A005258(n*p^(r-1)) (mod p^(3*r)) for all primes p >= 5 and all positive integers n and r
and
2) A005258(n*p^r - 1) == A005258(n*p^(r-1) - 1) (mod p^(3*r)) for all primes p >= 5 and all positive integers n and r.
We conjecture that the present sequence satisfies the same pair of supercongruences. Some examples are given below.
FORMULA
a(n) ~ (2/3 + sqrt(31) * cos(arccos(1597/(434*sqrt(31)))/3)/6) * (19 + 28*sqrt(7/3) * cos(arccos(3*sqrt(3/7)/2)/3))^n / (Pi*n)^2. - Vaclav Kotesovec, Oct 16 2025
a(n) ~ (17 + 349/(4*(13*cos(Pi/7) - 8))) * 2^(7*n) * cos(Pi/7)^(7*n) / (26 * Pi^2 * n^2). - Vaclav Kotesovec, May 08 2026
EXAMPLE
Examples of supercongruences:
a(11) - a(1) = 60519806861966105 - 5 = (2^2)*(3^2)*(5^2)*(11^3)*197*256454747 == 0 (mod 11^3).
a(10) - a(0) = 1180189308268609 - 1 = (2^6)*3*(11^3)*37*2789*44753 == 0 (mod 11^3).
MAPLE
MATHEMATICA
Table[Sum[Binomial[n, k]^2 * Binomial[n+k, k] * HypergeometricPFQ[{-n, k-n, n+1}, {1, 1}, 1], {k, 0, n}], {n, 0, 20}] (* Vaclav Kotesovec, Oct 16 2025 *)
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Peter Bala, Sep 24 2024
STATUS
approved
