OFFSET
1,1
COMMENTS
Odd composite numbers k such that 5^((k-1)/2) == (5/k) = 1 (mod k), where (5/k) is the Jacobi symbol (or Kronecker symbol).
LINKS
Jianing Song, Table of n, a(n) for n = 1..1000
EXAMPLE
29539 is a term because 29539 = 109*271 is composite, 29539 == 9 (mod 10), and 5^((29539-1)/2) == 1 (mod 29539).
MATHEMATICA
q[k_] := MemberQ[{1, 9}, Mod[k, 10]] && CompositeQ[k] && PowerMod[5, (k-1)/2, k] == 1; Select[Range[142000], q] (* Amiram Eldar, Mar 21 2026 *)
PROG
(PARI) isA375915(k) = (k>1) && !isprime(k) && (k%10==1 || k%10==9) && Mod(5, k)^((k-1)/2) == 1
CROSSREFS
KEYWORD
nonn
AUTHOR
Jianing Song, Sep 02 2024
STATUS
approved
