OFFSET
1,1
COMMENTS
Odd composite numbers k such that 5^((k-1)/2) == (5/k) = -1 (mod k), where (5/k) is the Jacobi symbol (or Kronecker symbol).
LINKS
Jianing Song, Table of n, a(n) for n = 1..1000
EXAMPLE
216457 is a term because 216457 = 233*929 is a composite, 216457 == 7 (mod 10), and 5^((216457-1)/2) == -1 (mod 216457).
MATHEMATICA
q[k_] := MemberQ[{3, 7}, Mod[k, 10]] && CompositeQ[k] && PowerMod[5, (k-1)/2, k] == k-1; Select[Range[8*10^6], q] (* Amiram Eldar, Mar 21 2026 *)
PROG
(PARI) isA375916(k) = !isprime(k) && (k%10==3 || k%10==7) && Mod(5, k)^((k-1)/2) == -1
CROSSREFS
KEYWORD
nonn
AUTHOR
Jianing Song, Sep 02 2024
STATUS
approved
