OFFSET
1,3
LINKS
Andrew Howroyd, Table of n, a(n) for n = 1..1000
FORMULA
a(2*n) = 6*binomial(5*n+1, n-1)/(5*n+1); a(2*n+1) = 4*binomial(5*n+4, n)/(5*n+4).
PROG
(PARI) a(n)=my(m=n\2); if(n%2==0, 6*binomial(5*m+1, m-1)/(5*m+1), 4*binomial(5*m+4, m)/(5*m+4))
CROSSREFS
KEYWORD
nonn
AUTHOR
Andrew Howroyd, Feb 08 2024
STATUS
approved