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A367118 Place n points in general position on each side of an equilateral triangle, and join every pair of the 3*n+3 boundary points by a chord; sequence gives number of regions in the resulting planar graph. 8
1, 13, 82, 307, 841, 1891, 3718, 6637, 11017, 17281, 25906, 37423, 52417, 71527, 95446, 124921, 160753, 203797, 254962, 315211, 385561, 467083, 560902, 668197, 790201, 928201, 1083538, 1257607, 1451857, 1667791, 1906966, 2170993, 2461537, 2780317, 3129106, 3509731, 3924073, 4374067 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
"In general position" implies that the internal lines (or chords) only have simple intersections. There is no interior point where three or more chords meet.
LINKS
Scott R. Shannon, Image for n = 1.
Scott R. Shannon, Image for n = 2.
Scott R. Shannon, Image for n = 5.
FORMULA
Conjecture: a(n) = (1/4)*(9*n^4 + 12*n^3 + 15*n^2 + 12*n + 4).
a(n) = A367119(n) - A367117(n) + 1 by Euler's formula.
CROSSREFS
Cf. A367117 (vertices), A367119 (edges), A091908, A092098, A331782, A367015.
If the boundary points are equally spaced, we get A274585, A092866, A274586, A092867. - N. J. A. Sloane, Nov 09 2023
Sequence in context: A052255 A362545 A082203 * A101102 A213572 A142085
KEYWORD
nonn
AUTHOR
STATUS
approved

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Last modified September 8 17:50 EDT 2024. Contains 375753 sequences. (Running on oeis4.)