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A365374
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Numbers k such that squaring each digit and concatenating them forms a palindrome.
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1
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0, 1, 2, 3, 11, 19, 22, 28, 33, 37, 41, 72, 101, 111, 121, 131, 199, 202, 212, 222, 232, 288, 303, 313, 323, 327, 333, 377, 441, 461, 732, 772, 1001, 1111, 1191, 1221, 1281, 1331, 1371, 1411, 1721, 1919, 1999, 2002, 2112, 2192, 2222, 2282, 2332, 2372, 2412, 2722, 2828, 2888
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OFFSET
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1,3
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COMMENTS
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The sequence is infinite since if k is a term then so is 1k1.
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LINKS
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EXAMPLE
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k(6) = 19 becomes 181 as 1^2 = 1 and 9^2 = 81;
k(7) = 22 becomes 44 as 2^2 = 4 and 2^2 = 4;
k(8) = 28 becomes 464 as 2^2 = 4 and 8^2 = 64; etc.
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MATHEMATICA
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Select[Range[0, 3000], PalindromeQ@FromDigits@Flatten[IntegerDigits/@(IntegerDigits@#^2)]&]
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PROG
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(Python)
def ok(n): return (s:="".join(str(int(d)**2) for d in str(n))) == s[::-1]
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CROSSREFS
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KEYWORD
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base,nonn
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AUTHOR
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STATUS
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approved
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