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A360826 a(1) = 1, a(n) = (k+1)*(2k+1), where k = Product_{i=1..n-1} a(i). 1
1, 6, 91, 597871, 213122969971321411, 9680343693975641657052402556458789711774336036960631 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
A sequence of pairwise relatively prime triangular (and also hexagonal) numbers.
As a clarification to the problem definition by Sierpinski, here we show that only one triangular (hexagonal) seed is needed to produce such a sequence.
This sequence can be used for proving the infinitude of primes.
In general: Let m = 2q, for any q > 0. There are infinitely many sequences of pairwise coprime m-gonal numbers, whose first term is any positive m-gonal number and whose general term is of the form a(n) = (k + 1)*((q - 1)*k + 1)), where k = Product_{i=1..n-1} a(i).
REFERENCES
W. Sierpinski, 250 Problems in Elementary Number Theory. New York: American Elsevier, 1970. Problem #42.
LINKS
FORMULA
a(1) = 1, a(n) = (k+1)*(2k+1), where k = Product_{i=1..n-1} a(i).
a(n) ~ c^(3^n), where c = 1.1784502032269064445225839284451956694752084180050932315805089054871825498... - Vaclav Kotesovec, May 05 2023
MATHEMATICA
a[1]=1; a[n_]:=Module[{k=Product[a[i], {i, 1, n-1}]}, (k+1)*(2*k+1)];
a/@Range[6]
Join[{1}, RecurrenceTable[{a[2] == 6, a[n+1] == (1 + a[n]*(Sqrt[1 + 8*a[n]] - 3)/4) * (1 + 2*a[n]*(Sqrt[1 + 8*a[n]] - 3)/4)}, a, {n, 2, 8}]] (* Vaclav Kotesovec, May 05 2023 *)
CROSSREFS
Sequence in context: A006151 A005327 A182263 * A171910 A278683 A280214
KEYWORD
nonn
AUTHOR
Ivan N. Ianakiev, Feb 22 2023
STATUS
approved

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Last modified April 23 06:58 EDT 2024. Contains 371906 sequences. (Running on oeis4.)