OFFSET
-1,1
COMMENTS
The first Morley triangle, also called the Morley triangle, of any triangle is always equilateral (see Wikipedia link).
If an isosceles right triangle ABC has side lengths (a, a, a*sqrt(2)), then it has a circumradius R = a*sqrt(2)/2, and an area A = a^2/2, and its first Morley triangle has side a' = 8*R*sin(Pi/6)*sin(Pi/12)*sin(Pi/12) and an area A' = a'^2 * sqrt(3)/4 = a^2 * (7*sqrt(3) - 12)/8. This gives the ratio A'/A = (7*sqrt(3)-12)/4 (see Illustration).
This ratio is not equal to the square of the ratio of the perimeters = A360828^2 because the Morley triangle and the isosceles right triangle are not homothetic.
LINKS
FORMULA
Equals (7*sqrt(3) - 12)/4.
EXAMPLE
0.03108891324553526367303109763527664214990919416...
MAPLE
evalf((7/4)*sqrt(3) - 3, 100);
MATHEMATICA
RealDigits[(7*Sqrt[3] - 12)/4, 10, 100][[1]] (* Amiram Eldar, Mar 09 2023 *)
PROG
(PARI) 7*sqrt(3)/4 - 3 \\ Charles R Greathouse IV, Feb 05 2025
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
Bernard Schott, Mar 09 2023
EXTENSIONS
a(96)-a(97) from Georg Fischer, Feb 08 2025
STATUS
approved