login
A359020
Number of inequivalent tilings of a 4 X n rectangle using integer-sided square tiles.
11
1, 1, 4, 6, 13, 39, 115, 295, 861, 2403, 7048, 20377, 60008, 175978, 519589, 1532455, 4531277, 13395656, 39639758, 117301153, 347248981, 1028011708, 3043852214, 9012879842, 26689014028, 79033362580, 234045889421, 693101137571, 2052569508948
OFFSET
0,3
COMMENTS
If only symmetries of the rectangle are considered then a(4) would be 18.
LINKS
Index entries for linear recurrences with constant coefficients, signature (3,5,-13,-9,3,3,27,18,6,0,-12,-6,-12,-6,0,1,3,1,1).
FORMULA
For even n > 4:
a(n) = (A054856(n) + compo(n) + 4 * A054856((n - 2) / 2) +
2 * A054856((n - 4) / 2) + 2 * A054856(n / 2) +
2 * Sum_{k=0..(n - 2) / 2} (A054856(k))) / 4;
For odd n > 4:
a(n) = (A054856(n) + compo(n) + 2 * A054856((n - 3) / 2) +
2 * A054856((n - 1) / 2) + 2 * Sum_ {k=0..(n - 3) / 2} (A054856(k))) / 4,
Where compo(n) is the number of distinct compositions of n as a sum of 1, 2, (1+1) and 4.
G.f.: -5*x^4 + (1 - 2*x - 4*x^2 + 2*x^3 + 2*x^4 + 13*x^5 + 16*x^6 + x^7 - 5*x^8 - 13*x^9 - 7*x^10 - 2*x^11 + 3*x^13 + x^14 + x^15)/((1 + x)*(1 + x^2)*(1 - 3*x + x^4)*(1 - x - 2*x^2 - x^4)*(1 - 3*x^2 + x^8)). - Andrew Howroyd, Nov 16 2025
EXAMPLE
a(3) is 6 because of:
+-+-+-+ +-+-+-+ +-+-+-+ +-+-+-+ +-+-+-+ +-+-+-+
| | | | | | | | | | | | | | | | | | |
+-+-+-+ + + + +-+ + +-+ + +-+ +-+-+-+
| | | | | | | | | | | | | | | | | |
+-+-+-+ + + +-+-+-+ +-+-+-+ +-+-+-+ + +-+
| | | | | | | | | | | | | | | | | | |
+-+-+-+ +-+-+-+ + +-+ +-+ + +-+-+-+ +-+-+-+
| | | | | | | | | | | | | | | | | | | | | |
+-+-+-+ +-+-+-+ +-+-+-+ +-+-+-+ +-+-+-+ +-+-+-+
PROG
(PARI) Vec(-5*x^4+(1-2*x-4*x^2+2*x^3+2*x^4+13*x^5+16*x^6+x^7-5*x^8-13*x^9-7*x^10-2*x^11+3*x^13+x^14+x^15)/((1+x)*(1+x^2)*(1-3*x+x^4)*(1-x-2*x^2-x^4)*(1-3*x^2+x^8))+O(x^99)) \\ Charles R Greathouse IV, May 13 2026
CROSSREFS
Column k = 4 of A227690.
Sequences for fixed and free (inequivalent) tilings of m X n rectangles, for 2 <= m <= 10:
Sequence in context: A105205 A302311 A160805 * A246424 A012776 A240198
KEYWORD
nonn,easy
AUTHOR
John Mason, Dec 12 2022
STATUS
approved