A358067 a(n) is the smallest m such that A144261(m) = n.

1, 15, 14, 33, 22, 17, 73, 49, 13, 11, 529, 31, 397, 293, 241, 199, 1633, 53, 3727, 761, 331, 491, 4343, 431, 1943, 887, 383, 3659, 3809, 377, 15863, 9419, 2713, 2993, 26753, 1583, 30311, 5297, 8971, 2753, 5363, 983, 11603, 4919, 18314, 14657, 59303, 1499, 99179

Offset

1,2

Comments

In other words, a(n) is the smallest element m of the set of the integers k that satisfy {A144261(k) = n and n * k is a Niven number} (see Example section).

Same question as in A144261: does a(n) exist for all n?

Links

Table of n, a(n) for n=1..49.

Giovanni Resta, Harshad numbers.

Example

A144261(15) = A144261(25) = A144261(35) = A144261(51) = ... = 2 because 15, 25, 35, 51, ... are not Niven numbers and 2 is the smallest integer such that 2*15=30, 2*25=50, 2*35=70, 2*51=102, ..., are Niven (or Harshad) numbers. Since 15 is the least integer that, when multiplied by 2, yields a Niven number (2*15), a(2) = 15.

Mathematica

f[n_] := Module[{k = 1, p}, While[! Divisible[p = k*n, Plus @@ IntegerDigits[p]], k++]; k]; seq[len_, nmax_] := Module[{s = Table[0, {len}], c = 0, n = 1, i}, While[c < len && n < nmax, i = f[n]; If[i <= len && s[[i]] == 0, c++; s[[i]] = n]; n++]; s]; seq[50, 10^6] (* Amiram Eldar, Oct 29 2022 *)

Prog

(PARI) f(n) = my(k=1); while ((k*n) % sumdigits(k*n), k++); k; \\ A144261
a(n) = my(k=1); while (f(k) != n, k++); k; \\ Michel Marcus, Oct 31 2022
(Python)
from itertools import count
def A358067(n): return next(filter(lambda m:n==next(filter(lambda k:not (r:=k*m) % sum(int(d) for d in str(r)), count(1))), count(1))) # Chai Wah Wu, Nov 04 2022

Crossrefs

Cf. A005349 (Niven numbers), A144261.

Sequence in context: A087979 A291490 A373161 * A048294 A248391 A201345

Adjacent sequences: A358064 A358065 A358066 * A358068 A358069 A358070

Keyword

nonn,base

Author

Bernard Schott, Oct 29 2022

Extensions

More terms from Amiram Eldar, Oct 29 2022

Status

approved