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A357062
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Number of ordered solutions to n = x*y*z + x + y + z in positive integers.
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2
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0, 0, 0, 0, 1, 0, 3, 0, 3, 3, 3, 0, 9, 0, 4, 6, 6, 0, 9, 3, 9, 6, 3, 0, 18, 3, 6, 6, 9, 3, 15, 0, 9, 12, 6, 6, 19, 0, 3, 9, 21, 0, 18, 0, 12, 12, 6, 6, 21, 6, 9, 12, 9, 0, 24, 6, 18, 6, 3, 6, 33, 6, 6, 12, 15, 6, 18, 0, 15, 15, 15, 0, 33, 6, 6, 18, 13, 6, 21, 3, 21, 9, 9, 0, 36, 12, 9, 12, 18, 9, 27, 6, 9, 9, 6
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OFFSET
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0,7
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LINKS
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FORMULA
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Conrey & Shah prove that a(n) << n^(1.3) * log n * (log log n)^4, and conjecture that a(n) << n^e for any e > 0.
Conrey & Shah prove that the average value of a(n) is (log n)^2/2, in the sense that Sum_{k <= n} a(k) ~ n*(log n)^2/2.
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EXAMPLE
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6 = 2*1*1 + 2 + 1 + 1 = 1*2*1 + 1 + 2 + 1 = 1*1*2 + 1 + 1 + 2, so a(6) = 3.
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PROG
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(PARI) a(n)=sum(x=1, (n-1)\2, my(s); for(y=1, x, my(m=x*y+1); if(m+x+y>n, break); my(N=n-y-x, z); if(N%m, next); z=N/m; z<=y && s += [1, 3, 6][#Set([x, y, z])]); s)
(Python)
from sympy.utilities.iterables import combinations_with_replacement
from math import prod
def A357062(n): return sum(max(1, 3*(len(set(d))-1)) for d in combinations_with_replacement(range(1, n+1), 3) if prod(d)+sum(d) == n) # Chai Wah Wu, Oct 21 2022
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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