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A356553
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For any n > 0, let b > 1 be the least base where the sum of digits of n divides n; a(n) is the sum of digits of n in base b.
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2
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1, 1, 1, 1, 1, 2, 1, 1, 1, 2, 1, 2, 1, 2, 3, 1, 1, 2, 1, 2, 3, 2, 1, 2, 5, 2, 1, 2, 1, 2, 1, 1, 3, 2, 5, 2, 1, 2, 3, 2, 1, 3, 1, 4, 3, 2, 1, 2, 1, 5, 3, 4, 1, 2, 5, 4, 3, 2, 1, 4, 1, 2, 3, 1, 5, 2, 1, 2, 3, 10, 1, 2, 1, 2, 5, 4, 7, 6, 1, 2, 3, 2, 1, 3, 5, 2, 3
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OFFSET
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1,6
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COMMENTS
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See A356552 for the corresponding bases.
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LINKS
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EXAMPLE
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For n = 14:
- we have:
b sum of digits divides 14?
-- ------------- -----------
2 3 no
3 4 no
4 5 no
5 6 no
6 4 no
7 2 yes
- so a(14) = 2.
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MATHEMATICA
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a[n_] := Module[{b = 2}, While[!Divisible[n, (s = Plus @@ IntegerDigits[n, b])], b++]; s]; Array[a, 100] (* Amiram Eldar, Sep 19 2022 *)
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PROG
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(PARI) a(n) = { for (b=2, oo, my (s=sumdigits(n, b)); if (n % s==0, return (s))) }
(Python)
from sympy.ntheory import digits
def a(n):
b = 2
while n != 0 and n%sum(digits(n, b)[1:]): b += 1
return sum(digits(n, b)[1:])
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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