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A355589 a(n) is the least distance of two nodes on the same grid line in an infinite triangular lattice of one-ohm resistors for which the resistance measured between the two nodes is greater than n ohms. 4
1, 38, 8632, 1991753, 459625866 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
The terms are obtained by a high-precision evaluation of the integral R(j,k) = (1/Pi) * Integral_{y=0..Pi/2} (1 - exp(-|j-k|*x)*cos((j+k)*y)) / (sinh(x)*cos(y)) dy, with x = arccosh(2/cos(y)-cos(y)), such that floor(R(m-1,0)) < floor(R(m,0)). The values of m for which this condition is satisfied are the terms of the sequence. See Atkinson and van Steenwijk (1999, page 491, Appendix B) for a Mathematica implementation of the integral.
LINKS
D. Atkinson and F. J. van Steenwijk, Infinite resistive lattices, Am. J. Phys. 67 (1999), 486-492. (See A211074 for an alternative link.)
EXAMPLE
a(0) = 1: R(1,0) = 1/3 is the first resistance > 0;
a(1) = 38: R(37,0) = 0.9980131561985..., R(38,0) = 1.0029141482654...;
a(2) = 8632: R(8631) = 1.99999787859849..., R(8632) = 2.000019169949784851...;
a(3) = 1991753: R(1991752) = 2.99999998586..., R(1991753) = 3.000000078131...;
a(4) = 459625866: R(459625865)=3.999999999731...; R(459625866)=4.000000000131....
Assuming a fitted asymptotic logarithmic growth of R(x,0) = log(x)/(Pi*sqrt(3)) + 0.334412..., a(5) is approximately 1.06*10^11, but 250 GByte of main memory is not enough for PARI's function intnum to compute the value of the integral for arguments of that size.
CROSSREFS
Cf. A355585, A355955 (same problem for square lattice).
Sequence in context: A173133 A221354 A096558 * A145120 A183581 A030260
KEYWORD
nonn,hard,more
AUTHOR
Hugo Pfoertner, Jul 23 2022
STATUS
approved

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Last modified July 21 20:59 EDT 2024. Contains 374475 sequences. (Running on oeis4.)