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 A350833 Run lengths of even terms in A350877 (half if even, add next prime if odd). 4
 0, 1, 3, 3, 2, 4, 1, 2, 1, 2, 1, 1, 1, 1, 1, 5, 1, 2, 1, 2, 1, 1, 2, 1, 5, 1, 2, 1, 1, 2, 1, 2, 6, 1, 2, 1, 2, 2, 5, 2, 5, 2, 1, 3, 2, 1, 2, 2, 4, 3, 3, 4, 1, 2, 5, 1, 1, 1, 1, 1, 3, 1, 3, 2, 1, 3, 2, 2, 3, 1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 2, 4, 3, 3, 1, 1, 1, 1, 1, 2, 4, 1, 1, 1, 1, 1, 1, 3, 1, 1, 2, 2, 1, 2, 2, 2, 1, 2 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,3 COMMENTS Equals first differences of indices of odd terms (A350616) minus one. After the initial 0, also equals the 2-valuation (A007814) of A350618, the terms following odd terms in A350877. Record values are a(1) = 0, a(2) = 1, a(3) = 3, a(6) = 4, a(16) = 5, a(33) = 6, a(146) = 7, a(243) = 11, a(1596) = 12, a(2092) = 13, ... The first occurrences of the other values are: a(5) = 2, a(8) = 510, a(9) = 667, a(10) = 1526. No others up to n = 33000. - M. F. Hasler, Jan 24 2022 LINKS M. F. Hasler, Table of n, a(n) for n = 1..10000 FORMULA a(n) = A350616(n+1) - A350616(n) - 1 = A007814(A350618(n-1)) for n > 1. EXAMPLE Between the first odd term, A350877(1) = 1, and second odd term, A350877(2) = 3, there are no even terms, therefore a(1) = 0. Between the second and third odd term, A350877(4) = 3, there is one even term, A350877(3) = 6, therefore a(2) = 1. PROG (PARI) A350833_upto(N)={N=A350616_upto(N); [N[k]-N[k-1]-1|k<-[2..#N]]} CROSSREFS Cf. A007814, A350877, A350616, A350618. Sequence in context: A086632 A038699 A249803 * A064655 A207335 A049604 Adjacent sequences: A350830 A350831 A350832 * A350834 A350835 A350836 KEYWORD nonn AUTHOR M. F. Hasler, Jan 23 2022 STATUS approved

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Last modified September 26 15:01 EDT 2023. Contains 365660 sequences. (Running on oeis4.)