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A350178
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Take n and subtract the greatest square less than or equal to n. Repeat this process until 0 is reached. a(n) is the sum of all residues after subtractions.
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1
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0, 0, 1, 3, 0, 1, 3, 6, 4, 0, 1, 3, 6, 4, 6, 9, 0, 1, 3, 6, 4, 6, 9, 13, 12, 0, 1, 3, 6, 4, 6, 9, 13, 12, 9, 11, 0, 1, 3, 6, 4, 6, 9, 13, 12, 9, 11, 14, 18, 0, 1, 3, 6, 4, 6, 9, 13, 12, 9, 11, 14, 18, 17, 20, 0, 1, 3, 6, 4, 6, 9, 13, 12, 9, 11, 14, 18, 17, 20, 24, 16, 0, 1, 3, 6, 4, 6, 9, 13
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OFFSET
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0,4
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COMMENTS
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Let s_1,s_2,s_3,...,s_m be the greedy partition of n into squares (n = s_1+s_2+s_3+...+s_m) such that s_1 >= s_2 >= s_3 >= ... >= s_m then a(n) = 0*s_1 + 1*s_2 + 2*s_3 + ... + (m-1)*s_m.
This sequence contains only numbers which can be written in the form c_1^2 + 2*c_2^2 + ... + m*c_m^2 with c_1 >= c_2 >= c_m. This excludes 2,5,7,8,... .
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LINKS
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FORMULA
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a(n) = n - r^2 + a(n - r^2) = a(n - r^2 + (b + r)^2) = a(n + b^2 + 2*b*r), r = floor(sqrt(n)), for any b >= 0. True because a(n) depends only on the distance to the next square <= n.
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EXAMPLE
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a(41): 41 - 6^2 = 5; 5 - 2^2 = 1; 1 - 1^2 = 0 -> 5+1 = 6 = a(41).
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PROG
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(PARI) A350178(n)={my(r=0); while(n-=sqrtint(n)^2, r+=n); r};
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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