login
A341898
Numbers that are the sum of five fourth powers in exactly ten ways.
6
954979, 1205539, 1574850, 1713859, 1863859, 1877394, 1882579, 2071939, 2109730, 2225859, 2288179, 2419954, 2492434, 2495939, 2605314, 2711394, 2784499, 2835939, 2847394, 2880994, 2924674, 3007474, 3061939, 3071379, 3074179, 3117235, 3127219, 3174834, 3190899
OFFSET
1,1
COMMENTS
Differs at term 5 because
1801459 = 1^4 + 4^4 + 5^4 + 28^4 + 33^4
= 1^4 + 4^4 + 12^4 + 23^4 + 35^4
= 1^4 + 7^4 + 16^4 + 30^4 + 31^4
= 1^4 + 16^4 + 18^4 + 19^4 + 35^4
= 3^4 + 6^4 + 18^4 + 21^4 + 35^4
= 5^4 + 7^4 + 19^4 + 24^4 + 34^4
= 5^4 + 9^4 + 14^4 + 29^4 + 32^4
= 7^4 + 9^4 + 16^4 + 25^4 + 34^4
= 7^4 + 14^4 + 16^4 + 21^4 + 35^4
= 8^4 + 9^4 + 20^4 + 29^4 + 31^4
= 10^4 + 19^4 + 19^4 + 21^4 + 34^4.
LINKS
David Consiglio, Jr., Table of n, a(n) for n = 1..10000
EXAMPLE
954979 = 1^4 + 2^4 + 11^4 + 19^4 + 30^4
= 1^4 + 7^4 + 18^4 + 25^4 + 26^4
= 3^4 + 8^4 + 17^4 + 20^4 + 29^4
= 4^4 + 8^4 + 13^4 + 25^4 + 27^4
= 4^4 + 9^4 + 10^4 + 11^4 + 31^4
= 6^4 + 6^4 + 15^4 + 21^4 + 29^4
= 7^4 + 10^4 + 18^4 + 19^4 + 29^4
= 11^4 + 11^4 + 20^4 + 22^4 + 27^4
= 16^4 + 17^4 + 17^4 + 24^4 + 25^4
= 18^4 + 19^4 + 20^4 + 23^4 + 23^4
so 954979 is a term.
PROG
(Python)
from itertools import combinations_with_replacement as cwr
from collections import defaultdict
keep = defaultdict(lambda: 0)
power_terms = [x**4 for x in range(1, 1000)]
for pos in cwr(power_terms, 5):
tot = sum(pos)
keep[tot] += 1
rets = sorted([k for k, v in keep.items() if v == 10])
for x in range(len(rets)):
print(rets[x])
CROSSREFS
KEYWORD
nonn
AUTHOR
STATUS
approved