OFFSET
1,2
COMMENTS
Conjecture: the sum of row n equals A138879(n), the sum of all parts in the last section of the set of partitions of n.
EXAMPLE
Triangle begins:
1;
3, 0;
4, 0, 1;
7, 0, 3, 1;
6, 0, 4, 3, 2;
12, 0, 7, 4, 6, 2;
8, 0, 6, 7, 8, 6, 4;
15, 0, 12, 6, 14, 8, 12, 4;
13, 0, 8, 12, 12, 14, 16, 12, 7;
18, 0, 15, 8, 24, 12, 28, 16, 21, 8;
12, 0, 13, 15, 16, 24, 14, 28, 28, 24, 12;
28, 0, 18, 13, 30, 16, 48, 24, 49, 32, 36, 14;
...
For n = 6 the calculation of every term of row 6 is as follows:
--------------------------
k A002865 T(6,k)
--------------------------
1 1 * 12 = 12
2 0 * 6 = 0
3 1 * 7 = 7
4 1 * 4 = 4
5 2 * 3 = 6
6 2 * 1 = 2
. A000203
--------------------------
The sum of row 6 is 12 + 0 + 7 + 4 + 6 + 2 = 31, equaling A138879(6) = 31.
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Omar E. Pol, Jan 07 2021
STATUS
approved