OFFSET
0,4
COMMENTS
LINKS
Stefano Spezia, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (1,1,-1,1,-1).
FORMULA
a(n) = Fibonacci(k+2) + Fibonacci(k)*(n mod 2) - 1, where k = floor(n/2). - Wesley Ivan Hurt, Dec 09 2020
G.f.: x^2*(1 + x - x^2)/((1 - x)*(1 - x^2 - x^4)). - Andrew Howroyd, Nov 18 2025
MATHEMATICA
Block[{b = {0, 2}, a = {}}, Do[If[EvenQ[i], AppendTo[b, Total@ b[[-2 ;; -1]] + 1 ]; AppendTo[a, Fibonacci[i/2 + 1] - 1], AppendTo[a, b[[(i - 1)/2]]]], {i, 2, 53}]; a] (* Michael De Vlieger, Dec 09 2020 *)
Table[With[{k=Floor[n/2]}, Fibonacci[k+2]+Fibonacci[k]Mod[n, 2]-1], {n, 0, 60}] (* Harvey P. Dale, Jun 24 2025 *)
PROG
(PARI) a(n)=fibonacci(n\2+2) + if(n%2, fibonacci((n-1)/2)) - 1; \\ Andrew Howroyd, Nov 18 2025
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, Dec 09 2020
STATUS
approved
