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A339082
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a(n) is the number m such that F(prime(m)) is the greatest prime Fibonacci divisor of F(n)^2 + 1 where F(n) is the n-th Fibonacci number, or 0 if no such prime factor exists.
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2
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2, 2, 3, 3, 4, 4, 3, 4, 5, 5, 6, 6, 5, 6, 7, 7, 3, 7, 7, 4, 9, 9, 4, 9, 9, 3, 10, 10, 2, 10, 10, 5, 4, 5, 5, 4, 6, 6, 0, 6, 14, 14, 3, 14, 15, 15, 4, 15, 15, 7, 4, 7, 7, 5, 2, 5, 5, 2, 2, 0, 4, 4, 6, 6, 4, 6, 9, 9, 0, 9, 9, 0, 3, 3, 5, 5, 3, 5, 5, 2, 23, 23, 7
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OFFSET
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1,1
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COMMENTS
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If a(n) > 0, then prime(a(n)) = A335568(n).
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LINKS
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FORMULA
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EXAMPLE
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a(15) = 7 because F(15)^2 + 1 = 610^2 + 1 = 372101 = 233*1597, 1597 = F(17) is the greatest prime Fibonacci divisor of 372101 and 17 is the 7th prime.
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MAPLE
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a:= proc(n) local i, F, m, t; F, m, t:=
[1, 2], 0, (<<0|1>, <1|1>>^n)[2, 1]^2+1;
for i from 3 while F[2]<=t do if isprime(F[2]) and
irem(t, F[2])=0 then m:=i fi; F:= [F[2], F[1]+F[2]]
od; numtheory[pi](m)
end:
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MATHEMATICA
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a[n_] := Module[{i, F = {1, 2}, m = 0, t}, t = MatrixPower[{{0, 1}, {1, 1}}, n][[2, 1]]^2 + 1; For[i = 3, F[[2]] <= t, i++, If[PrimeQ[F[[2]]] && Mod[t, F[[2]]] == 0, m = i]; F = {F[[2]], F[[1]] + F[[2]]}]; PrimePi[m]];
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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