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A335967 Irregular table read by rows; if the binary representation of n encodes the last row of a tiling of a staircase polyomino, then the n-th row contains the numbers k whose binary representation encode possible penultimate rows. 3
0, 1, 1, 2, 2, 3, 2, 3, 4, 5, 4, 5, 6, 7, 5, 6, 5, 4, 5, 6, 7, 8, 9, 10, 11, 10, 9, 10, 13, 14, 8, 9, 10, 11, 12, 13, 14, 15, 10, 13, 11, 12, 11, 10, 8, 9, 10, 11, 9, 10, 13, 12, 13, 14, 15, 16, 17, 18, 19, 18, 21, 22, 20, 21, 22, 23, 21, 20, 19, 20, 27, 28 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,4
COMMENTS
We consider tilings of staircase polyominoes as described in A335547, and encode rows of such tilings as described in A336479.
LINKS
Rémy Sigrist, Table of n, a(n) for n = 1..6766 (rows 1..2^10)
FORMULA
A336479(n) = Sum_{k = 1..A337131(n)} A336479(T(n, k)).
EXAMPLE
Triangle begins:
1: [0]
2: [1]
3: [1]
4: [2]
5: [2, 3]
6: [2]
7: [3]
8: [4]
9: [5]
10: [4, 5, 6, 7]
11: [5, 6]
12: [5]
13: [4, 5]
...
For n = 13, the binary representation of 13 is "1101", so we consider the tilings of a size 4 staircase polyomino whose base has the following shape:
.....
. .
. .....
. .
+---+ .....
| | .
| +---+---+---+
| 1 1 | 0 | 1 |
+-------+---+---+
There are two possible penultimate rows:
..... .....
. . . .
. ..... . .....
. | . . .
+---+ +---+ +---+---+---+
| 1 | 0 0 | | 1 | 0 | 1 |
| +---+---+---+ | +---+---+---+
| | | | | | | |
+-------+---+---+, +-------+---+---+
so the 13th row contains 4 and 5 ("100" and "101" in binary).
PROG
(PARI) See Links section.
CROSSREFS
Cf. A101211, A335547, A336479, A337131 (row lengths).
Sequence in context: A318287 A048621 A308048 * A319611 A337102 A239495
KEYWORD
nonn,base,tabf,look
AUTHOR
Rémy Sigrist, Sep 14 2020
STATUS
approved

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Last modified April 23 16:40 EDT 2024. Contains 371916 sequences. (Running on oeis4.)