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A335336
Carmichael numbers k such that k+1 is divisible by gpf(k)+1, where gpf = A006530.
1
687979968481, 1928376089641, 2638625591701, 3148470889201, 3152088903601, 14682521533681, 19656816822721, 37333372057201, 47003559452641, 80643055074121, 129235662445121, 140940741166849, 196945133626801, 336301807660741, 345186571310209, 439931062854361
OFFSET
1,1
COMMENTS
Are there any Carmichael numbers k with exactly four prime factors such that k+1 is divisible by gpf(k)+1?
Richard J. McIntosh and Mitra Dipra found the following base 2 Fermat pseudoprimes with exactly four prime factors satisfying s-1 | k-1 and s+1 | k+1, where s is the largest prime factor of k: 988679226253951, 3143193486942417481, 44307784380481317090001.
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..3150 (terms below 10^22, calculated using data from Claude Goutier; terms 1..459 from Daniel Suteu)
Richard J. McIntosh and Mitra Dipra, Carmichael numbers with p+1|n+1, Journal of Number Theory, Volume 147, February 2015, Pages 81-91.
Wikipedia, Carmichael number.
EXAMPLE
For k = 687979968481 = 13 * 29 * 71 * 181 * 211 * 673, which is a Carmichael number, we have gpf(k) = 673. Thereafter we have gpf(k)+1 = 2 * 337 and k+1 = 2 * 337 * 347 * 911 * 3229, satisfying gpf(k)+1 | k+1.
CROSSREFS
KEYWORD
nonn
AUTHOR
Daniel Suteu, Jun 04 2020
STATUS
approved