OFFSET
1,1
COMMENTS
Proof that any odd perfect number, if such numbers exist at all, has to reside in this sequence: As all terms in A228058 are = 1 modulo 4 (their binary expansion ends as "01"), and taking sigma of an odd perfect number would multiply it by two (shift one bit-position left), the base-2 expansion of that result would end as "010", i.e., sigma(k) modulo 8 should be 2 (not 6) for such numbers k.
LINKS
PROG
(PARI) isA332228(n) = ((n%2)&&!isprimepower(n)&&2==(sigma(n)%8));
CROSSREFS
KEYWORD
nonn
AUTHOR
Antti Karttunen, Feb 13 2020
STATUS
approved