

A331430


Triangle read by rows: T(n, k) = (1)^(k+1)*binomial(n,k)*binomial(n+k,k) (n >= k >= 0).


6



1, 1, 2, 1, 6, 6, 1, 12, 30, 20, 1, 20, 90, 140, 70, 1, 30, 210, 560, 630, 252, 1, 42, 420, 1680, 3150, 2772, 924, 1, 56, 756, 4200, 11550, 16632, 12012, 3432, 1, 72, 1260, 9240, 34650, 72072, 84084, 51480, 12870, 1, 90, 1980, 18480, 90090, 252252, 420420, 411840, 218790, 48620, 1, 110, 2970, 34320, 210210, 756756, 1681680, 2333760, 1969110, 923780, 184756
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OFFSET

0,3


COMMENTS

This is Table I of Ser (1933), page 92.
From Petros Hadjicostas, Jul 09 2020: (Start)
Essentially Ser (1933) in his book (and in particular for Tables IIV) finds triangular arrays that allow him to express the coefficients of various kinds of series in terms of the coefficients of other series.
He uses Newton's series (or some variation of it), factorial series, and inverse factorial series. Unfortunately, he uses unusual notation, and as a result it is difficult to understand what he is actually doing.
Rivoal (2008, 2009) essentially uses factorial series and transformations to other kinds of series to provide new proofs of the irrationality of log(2), zeta(2), and zeta(3). As a result, the triangular array T(n,k) appears in various parts of his papers.
We believe Table I (p. 92) in Ser (1933), regarding the numbers T(n,k), corresponds to four different formulas. We have deciphered the first two of them. (End)


REFERENCES

J. Ser, Les Calculs Formels des Séries de Factorielles. GauthierVillars, Paris, 1933, pp. 9293.


LINKS

Table of n, a(n) for n=0..65.
A. Buhl, Book review: J. Ser  Les calculs formels des séries de factorielles, L'Enseignement Mathématique, 32 (1933), p. 275.
L. A. MacColl, Review: J. Ser, Les calculs formels des séries de factorielles, Bull. Amer. Math. Soc., 41(3) (1935), p. 174.
L. M. MilneThomson, Review of Les calculs formels des séries de factorielles. By J. Ser. Pp. vii, 98. 20 fr. 1933. (GauthierVillars), The Mathematical Gazette, Vol. 18, No. 228 (May, 1934), pp. 136137.
J. Ser, Les Calculs Formels des Séries de Factorielles (Annotated scans of some selected pages)
Tanguy Rivoal, Applications arithmétiques de l'interpolation lagrangienne, preprint (2008); see pp. 1 and 15.
Tanguy Rivoal, Applications arithmétiques de l'interpolation lagrangienne, Int. J. Number Theory 5.2 (2009), 185208; see pp. 185 and 199.


FORMULA

T(n,k) can also be written as (1)^(k+1)*(n+k)!/(k!*k!*(nk)!).
From Petros Hadjicostas, Jul 09 2020: (Start)
Ser's first formula from his Table I (p. 92) is the following:
Sum_{k=0..n} T(n,k)*k!/(x*(x+1)*...*(x+k)) = (x1)*(x2)*...*(xn)/(x*(x+1)*...*(x+n)).
As a result, Sum_{k=0..n} T(n,k)/binomial(m+k, k) = 0 for m = 1..n.
Ser's second formula from his Table I appears also in Rivoal (2008, 2009) in a slightly different form:
Sum_{k=0..n} T(n,k)/(x + k) = (1)^(n+1)*(x1)*(x2)*...*(xn)/(x*(x+1)*...*(x+n)).
As a result, for m = 1..n, Sum_{k=0..n} T(n,k)/(m + k) = 0. (End)
T(n,k) = (1)^(k+1)*FallingFactorial(n+k,2*k)/(k!)^2.  Peter Luschny, Jul 09 2020
From Petros Hadjicostas, Jul 10 2020: (Start)
Peter Luschny's formula above is essentially the way the numbers T(n,k) appear in Eq. (7) on p. 86 of Ser's (1933) book. Eq. (7) is essentially equivalent to the first formula above (related to Table I on p. 92).
By inverting that formula (in some way), he gets
n!/(x*(x+1)*...*(x+n)) = Sum_{p=0..n} (1)^p*(2*p+1)*f_p(n+1)*f_p(x), where f_p(x) = (x1)*...*(xp)/(x*(x+1)*...*(x+p)). This is equivalent to Eq. (8) on p. 86 of Ser's book.
The rational coefficients A(n,p) = (2*p+1)*f_p(n+1) = (2*p+1)*(n*(n1)*...*(n+1p))/((n+1)*...*(n+1+p)) appear in Table II on p. 92 of Ser's book.
If we consider the coefficients T(n,k) and (1)^(p+1)*A(n,p) as infinite lower triangular matrices, then they are inverses of one another (see the example below). This means that, for m >= s,
Sum_{k=s..m} T(m,k)*(1)^(s+1)*A(k,s) = I(s=m) = Sum_{k=s..m} (1)^(k+1)*A(m,k)*T(k,s), where I(s=m) = 1, if s = m, and = 0, otherwise.
Without the (1)^p, we get the formula
1/(x+n) = Sum_{p=0..n} (2*p+1)*f_p(n+1)*f_p(x),
which apparently is the inversion of the second of Ser's formulas (related to Table I on p. 92).
In all of the above formulas, an empty product is by definition 1, so f_0(x) = 1/x. (End)


EXAMPLE

Triangle T(n,k) (with rows n >= 0 and columns k=0..n) begins:
1;
1, 2;
1, 6, 6;
1, 12, 30, 20;
1, 20, 90, 140, 70;
1, 30, 210, 560, 630, 252;
1, 42, 420, 1680, 3150, 2772, 924;
1, 56, 756, 4200, 11550, 16632, 12012, 3432;
...
From Petros Hadjicostas, Jul 11 2020: (Start)
Its inverse (from Table II, p. 92) is
1;
1/2, 1/2;
1/3, 1/2, 1/6;
1/4, 9/20, 1/4, 1/20;
1/5, 2/5, 2/7, 1/10, 1/70;
1/6, 5/14, 25/84, 5/36, 1/28, 1/252;
1/7, 9/28, 25/84, 1/6, 9/154, 1/84, 1/924;
... (End)


MATHEMATICA

Table[CoefficientList[Hypergeometric2F1[n, n + 1, 1, x], x], {n, 0, 9}] // Flatten (* Georg Fischer, Jan 18 2020 after Peter Luschny in A063007 *)


PROG

(MAGMA) /* As triangle: */ [[(1)^(k+1) * Factorial(n+k) / (Factorial(k) * Factorial(k) * Factorial(nk)): k in [0..n]]: n in [0.. 10]]; // Vincenzo Librandi, Jan 19 2020
(SageMath)
def T(n, k): return (1)^(k+1)*falling_factorial(n+k, 2*k)/factorial(k)^2
flatten([[T(n, k) for k in (0..n)] for n in (0..10)]) # Peter Luschny, Jul 09 2020


CROSSREFS

A063007 is the same triangle without the minus signs, and has much more information.
Columns 1 and 2 are A002378 and A033487; the last three diagonals are A002544, A002457, A000984.
Cf. A331431, A331432.
Sequence in context: A259569 A046651 A063007 * A202190 A089231 A052296
Adjacent sequences: A331427 A331428 A331429 * A331431 A331432 A331433


KEYWORD

sign,tabl


AUTHOR

N. J. A. Sloane, Jan 17 2020


EXTENSIONS

Thanks to Bob Selcoe, who noticed a typo in one of the entries, which, when corrected, led to an explicit formula for the whole of Ser's Table I.


STATUS

approved



