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A325490
Digits of one of the four 5-adic integers 6^(1/4) that is congruent to 2 mod 5.
10
2, 4, 0, 3, 0, 2, 0, 4, 0, 3, 0, 2, 2, 2, 1, 2, 1, 4, 0, 3, 4, 2, 1, 4, 1, 1, 2, 0, 0, 3, 0, 1, 1, 3, 1, 4, 4, 0, 2, 4, 0, 4, 1, 2, 0, 1, 2, 3, 2, 4, 2, 4, 1, 3, 0, 2, 1, 0, 3, 3, 3, 3, 0, 2, 2, 3, 1, 1, 4, 1, 1, 0, 1, 4, 0, 3, 3, 3, 0, 3, 0, 0, 4, 0, 3, 2, 3, 1
OFFSET
0,1
COMMENTS
One of the two square roots of A324026, where an A-number represents a 5-adic number. The other square root is A325491.
For k not divisible by 5, k is a fourth power in 5-adic field if and only if k == 1 (mod 5). If k is a fourth power in 5-adic field, then k has exactly 4 fourth-power roots.
LINKS
FORMULA
a(n) = (A325485(n+1) - A325485(n))/13^n.
For n > 0, a(n) = 4 - A325491(n).
EXAMPLE
The unique number k in [1, 5^3] and congruent to 2 modulo 5 such that k^4 - 6 is divisible by 5^3 is k = 22 = (42)_5, so the first three terms are 2, 4 and 0.
MAPLE
S:= select(t -> op([1, 3, 1], t)=2, [padic:-rootp(_Z^4-6, 5, 100)]):
op([1, 1, 3], S); # Robert Israel, Mar 23 2023
PROG
(PARI) a(n) = lift(sqrtn(6+O(5^(n+1)), 4) * sqrt(-1+O(5^(n+1))))\5^n
CROSSREFS
Digits of p-adic fourth-power roots:
A325489, this sequence, A325491, A325492 (5-adic, 6^(1/4));
A324085, A324086, A324087, A324153 (13-adic, 3^(1/4)).
Sequence in context: A007631 A281765 A155517 * A123514 A064178 A018220
KEYWORD
nonn,base
AUTHOR
Jianing Song, Sep 07 2019
STATUS
approved