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 A322092 Digits of one of the two 13-adic integers sqrt(-3). 7
 7, 9, 0, 6, 2, 5, 8, 8, 3, 4, 3, 10, 4, 7, 0, 9, 7, 8, 12, 6, 7, 11, 10, 6, 7, 3, 8, 3, 11, 11, 8, 6, 1, 9, 11, 0, 7, 10, 10, 6, 9, 1, 1, 4, 8, 7, 2, 2, 5, 3, 7, 5, 5, 5, 4, 12, 11, 12, 5, 5, 12, 3, 0, 2, 4, 11, 6, 11, 10, 2, 10, 3, 5, 10, 11, 2, 1, 8, 9, 7, 6 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 COMMENTS This square root of -3 in the 13-adic field ends with digit 7. The other, A322091, ends with digit 6. LINKS Seiichi Manyama, Table of n, a(n) for n = 0..10000 Peter Bala, Using Lucas polynomials to find the p -adic square roots of -1, -2 and -3/a>, Dec 2022. Wikipedia, p-adic number FORMULA a(n) = (A322090(n+1) - A322090(n))/13^n. For n > 0, a(n) = 12 - A322091(n). Equals A286838*A322087 = A286839*A322088. This 13-adic integer is the 13-adic limit as n -> oo of the integer sequence {L(13^n,7)}, where L(n,x) denotes the n-th Lucas polynomial, the n-th row polynomial of A114525. - Peter Bala, Dec 05 2022 EXAMPLE ...96AA70B9168BB38376AB76C879074A34388526097. PROG (PARI) a(n) = truncate(-sqrt(-3+O(13^(n+1))))\13^n CROSSREFS Cf. A114525, A286838, A286839, A322087, A322088, A322090, A322091. Sequence in context: A328110 A298740 A202283 * A104757 A199392 A120670 Adjacent sequences: A322089 A322090 A322091 * A322093 A322094 A322095 KEYWORD nonn,base,easy AUTHOR Jianing Song, Nov 26 2018 STATUS approved

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Last modified April 20 15:33 EDT 2024. Contains 371844 sequences. (Running on oeis4.)