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A321667
(3/2) * n^(2/3) rounded to nearest integer.
2
2, 2, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10, 10, 11, 11, 11, 12, 12, 12, 13, 13, 14, 14, 14, 14, 15, 15, 15, 16, 16, 16, 17, 17, 17, 18, 18, 18, 18, 19, 19, 19, 20, 20, 20, 20, 21, 21, 21, 21, 22, 22, 22, 22, 23, 23, 23, 23, 24, 24, 24, 24, 25, 25, 25, 25, 26, 26, 26, 26, 27
OFFSET
1,1
COMMENTS
This is an approximation to the solution of the "Concrete Math Club" casino problem given in A079631.
REFERENCES
R. L. Graham, D. E. Knuth and O. Patashnik, Concrete Mathematics. 2nd Edition. Addison-Wesley, Reading, MA, 1994. Section 3.2, pp. 74-76.
LINKS
MATHEMATICA
a[n_]:=Round[(3/2)*n^(2/3)]; Array[a, 50] (* Stefano Spezia, Nov 16 2018 *)
PROG
(PARI) for(j=1, 75, print1(round(1.5*j^(2/3)), ", "))
(Python) for n in range(1, 50): print(round((3/2)*n**(2/3)), end=', ') # Stefano Spezia, Nov 16 2018
CROSSREFS
Cf. A079631.
Sequence in context: A385072 A023190 A047783 * A194212 A194208 A057358
KEYWORD
nonn,easy
AUTHOR
Hugo Pfoertner, Nov 16 2018
STATUS
approved