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 A318571 a(n) = ceiling(log(2)/(log(1+n/100))). 0
 70, 36, 24, 18, 15, 12, 11, 10, 9, 8, 7, 7, 6, 6, 5, 5, 5, 5, 4, 4, 4, 4, 4, 4, 4, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 1 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS a(n) is the least positive integer k such that (1 + n/100)^k >= 2. LINKS Wikipedia, Rule of 72 FORMULA a(n) = 1 for n >= 100. EXAMPLE n  | a(n) | Rule of 72 (= 72/n) ------+------+---------------------     1 |   70 |         72     2 |   36 |         36     3 |   24 |         24     4 |   18 |         18     5 |   15 |         14.4     6 |   12 |         12     7 |   11 |         10.285714...     8 |   10 |          9     9 |    9 |          8    10 |    8 |          7.2    11 |    7 |          6.545454...    12 |    7 |          6 MAPLE seq(ceil(log(2)/(log(1+n/100))), n=1..100); # Muniru A Asiru, Aug 30 2018 MATHEMATICA Table[Ceiling[Log[2]/Log[1 + n/100]], {n, 100}] (* Vincenzo Librandi, Sep 01 2018 *) PROG (PARI) {a(n) = ceil(log(2)/(log(1+n/100)))} (MAGMA) [Ceiling(Log(2)/(Log(1+n/100))): n in [1..100]]; // Vincenzo Librandi, Sep 01 2018 CROSSREFS Sequence in context: A201097 A033390 A129352 * A156810 A252714 A245046 Adjacent sequences:  A318568 A318569 A318570 * A318572 A318573 A318574 KEYWORD nonn AUTHOR Seiichi Manyama, Aug 29 2018 STATUS approved

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Last modified December 15 11:43 EST 2019. Contains 329999 sequences. (Running on oeis4.)