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 A292682 Rule 230: (000, ..., 111) -> (0, 1, 1, 0, 0, 1, 1, 1), without extending to the right of input bit 0. 2
 0, 3, 6, 5, 12, 15, 10, 11, 24, 27, 30, 29, 20, 23, 22, 23, 48, 51, 54, 53, 60, 63, 58, 59, 40, 43, 46, 45, 44, 47, 46, 47, 96, 99, 102, 101, 108, 111, 106, 107, 120, 123, 126, 125, 116, 119, 118, 119, 80, 83, 86, 85, 92, 95, 90, 91, 88, 91, 94, 93, 92, 95, 94, 95, 192, 195, 198, 197, 204, 207 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,2 COMMENTS The orbit of 1 under this rule is A006977. The substitution rules 000 -> 0 and 100 -> 0 ensure that no (even or odd) input value can ever extend / "propagate" to the right, therefore it is not required to consider the additional digit to the right of input bit 0 (i.e., the cell which would have this bit 0 as left neighbor), as one would usually do in the context of elementary cellular automata (cf., e.g., A292680 vs. A292681). LINKS Eric Weisstein's World of Mathematics, Elementary Cellular Automaton EXAMPLE n        |         a(n)    0 =   0 |      0 =  0    1 =   1 |     11 =  3  (bits below 001 and 01(0) are on)    2 =  10 |    110 =  6  (1 below 001 and 010, 0 below 10(0))    3 =  11 |    101 =  5  (1 below 001 and 11(0), 0 below 011.)    4 = 100 |   1100 = 12  (as n = 1 and n = 2, shifted left once more)    5 = 101 |   1111 = 15  (1 below 001, 010 (twice) and 101)    6 = 110 |   1010 = 10  (as n = 3, shifted left once)    7 = 111 |   1011 = 11  (1 below 001, 111 and 11(0), 0 below 011). PROG (PARI) apply( A292682(n, r=230)=sum(i=0, logint(!n+n<<=1, 2)+1, bittest(r, bitand(n>>i, 7))<

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Last modified October 22 07:06 EDT 2021. Contains 348160 sequences. (Running on oeis4.)