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A291601
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Composite integers k such that 2^d == 2^(k/d) (mod k) for all d|k.
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3
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341, 1105, 1387, 2047, 2701, 3277, 4033, 4369, 4681, 5461, 7957, 8321, 10261, 13747, 13981, 14491, 15709, 18721, 19951, 23377, 31417, 31609, 31621, 35333, 42799, 49141, 49981, 60701, 60787, 65077, 65281, 68101, 80581, 83333, 85489, 88357, 90751, 104653, 123251, 129889
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OFFSET
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1,1
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COMMENTS
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Such k must be odd.
For d=1, we have 2^k == 2 (mod k), implying that k is a Fermat pseudoprime (A001567).
Every Super-Poulet number belongs to this sequence.
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LINKS
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MAPLE
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filter:= proc(n) local D, d;
if isprime(n) then return false fi;
D:= sort(convert(numtheory:-divisors(n), list));
for d in D while d^2 < n do
if 2 &^ d - 2 &^(n/d) mod n <> 0 then return false fi
od:
true
end proc:
select(filter, [seq(i, i=3..2*10^5, 2)]); # Robert Israel, Aug 28 2017
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MATHEMATICA
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filterQ[n_] := CompositeQ[n] && AllTrue[Divisors[n], PowerMod[2, #, n] == PowerMod[2, n/#, n]&];
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PROG
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(PARI) is(k) = {if(k == 1 || !(k%2) || isprime(k), return(0)); fordiv(k, d, if(d^2 <= k && Mod(2, k)^d != Mod(2, k)^(k/d), return(0))); 1; } \\ Amiram Eldar, Apr 22 2024
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CROSSREFS
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KEYWORD
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nonn,changed
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AUTHOR
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STATUS
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approved
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