OFFSET
1,1
COMMENTS
Partial sums of A180363.
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..500
FORMULA
From Jon E. Schoenfield, Dec 18 2016: (Start)
a(n) = Sum_{i=1..n} A180363(i).
MATHEMATICA
Accumulate[LucasL[Prime[Range[25]]]]
PROG
(Magma) [&+[Lucas(NthPrime(i)): i in [1..n]]: n in [1..30]];
CROSSREFS
KEYWORD
nonn
AUTHOR
Vincenzo Librandi, Dec 13 2016
STATUS
approved