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A269161
Formula for Wolfram's Rule 86 cellular automaton: a(n) = 4n XOR (2n OR n).
11
0, 7, 14, 11, 28, 27, 22, 19, 56, 63, 54, 51, 44, 43, 38, 35, 112, 119, 126, 123, 108, 107, 102, 99, 88, 95, 86, 83, 76, 75, 70, 67, 224, 231, 238, 235, 252, 251, 246, 243, 216, 223, 214, 211, 204, 203, 198, 195, 176, 183, 190, 187, 172, 171, 166, 163, 152, 159, 150, 147, 140, 139, 134, 131, 448, 455, 462, 459
OFFSET
0,2
COMMENTS
The sequence is injective: no value occurs more than once.
Fibbinary numbers (A003714) give all integers n>=0 for which a(n) = A048727(n) and for which a(n) = A269160(n).
FORMULA
a(n) = 4n XOR (2n OR n) = A003987(4*n, A003986(2*n, n)).
a(n) = 4*n XOR A163617(n).
Other identities. For all n >= 0:
a(2*n) = 2*a(n).
a(n) = A057889(A269160(A057889(n))). [Rule 86 is the mirror image of rule 30.]
MATHEMATICA
a[n_] := BitXor[4n, BitOr[2n, n]]; Table[a[n], {n, 0, 100}] (* Jean-François Alcover, Feb 23 2016 *)
PROG
(Scheme) (define (A269161 n) (A003987bi (* 4 n) (A003986bi (* 2 n) n))) ;; Where A003986bi and A003987bi are implementation of dyadic functions giving bitwise-OR (A003986) and bitwise-XOR (A003987) of their arguments.
(Python)
def A269161(n): return n<<2 ^ (n<<1 |n) # Chai Wah Wu, Jun 29 2022
CROSSREFS
Cf. A265281 (iterates starting from 1).
Cf. also A048727, A269160.
Sequence in context: A048727 A295123 A196178 * A307964 A225556 A064666
KEYWORD
nonn
AUTHOR
Antti Karttunen, Feb 20 2016
STATUS
approved