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A264443
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a(n) = n*(n + 5)*(n + 10)/6.
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7
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0, 11, 28, 52, 84, 125, 176, 238, 312, 399, 500, 616, 748, 897, 1064, 1250, 1456, 1683, 1932, 2204, 2500, 2821, 3168, 3542, 3944, 4375, 4836, 5328, 5852, 6409, 7000, 7626, 8288, 8987, 9724, 10500, 11316, 12173, 13072, 14014, 15000
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OFFSET
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0,2
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COMMENTS
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It is well-known, and easy to prove, that the product of 3 consecutive integers n*(n + 1)*(n + 2) is divisible by 6. It can be shown that the product of 3 integers in arithmetic progression n*(n + r)*(n + 2*r) is divisible by 6 if and only if r is not divisible by 2 or 3 (see A007310 for these numbers). This is the case r = 5.
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LINKS
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FORMULA
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O.g.f.: x*(6*x^2 - 16*x + 11)/(1 - x)^4.
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MAPLE
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seq( n*(n + 5)*(n + 10)/6, n = 1..40 );
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MATHEMATICA
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PROG
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(PARI) vector(100, n, n--; n*(n+5)*(n+10)/6) \\ Altug Alkan, Nov 15 2015
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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