A264448 a(n) = n*(n + 11)*(n + 22)*(n + 33)/24.

0, 391, 910, 1575, 2405, 3420, 4641, 6090, 7790, 9765, 12040, 14641, 17595, 20930, 24675, 28860, 33516, 38675, 44370, 50635, 57505, 65016, 73205, 82110, 91770, 102225, 113516, 125685, 138775, 152830, 167895, 184016, 201240, 219615, 239190, 260015, 282141, 305620, 330505

Offset

0,2

Comments

It is well-known, and easy to prove, that the product of 4 consecutive integers n*(n + 1)*(n + 2)*(n + 3) is divisible by 4!. It can be shown that the product of 4 integers in arithmetic progression n*(n + r)*(n + 2*r)*(n + 3*r) is divisible by 4! if and only if r is not divisible by 2 or 3 (see A007310 for these numbers). This is the case r = 11.

Links

Table of n, a(n) for n=0..38.

Index entries for linear recurrences with constant coefficients, signature (5,-10,10,-5,1).

Formula

O.g.f.: x*(391 - 1045*x + 935*x^2 - 280*x^3)/(1 - x)^5.

a(n) = 5*a(n-1)-10*a(n-2)+10*a(n-3)-5*a(n-4)+a(n-5) for n>4. - Vincenzo Librandi, Nov 16 2015

Maple

seq( n*(n + 11)*(n + 22)*(n + 33)/24, n = 0..38 );

Mathematica

Table[n (n + 11) (n + 22) (n + 33)/24, {n, 0, 40}] (* Vincenzo Librandi, Nov 16 2015 *)

Prog

(PARI) vector(100, n, n--; n*(n+11)*(n+22)*(n+33)/24) \\ Altug Alkan, Nov 15 2015
(Magma) [n*(n+11)*(n+22)*(n+33)/24: n in [0..40]]; // Vincenzo Librandi, Nov 16 2015

Crossrefs

Cf. A007310, A264443, A264444, A264445, A264446, A264447, A264449, A264450.

Sequence in context: A207575 A318174 A158004 * A160184 A187724 A035883

Adjacent sequences: A264445 A264446 A264447 * A264449 A264450 A264451

Keyword

nonn,easy

Author

Peter Bala, Nov 13 2015

Status

approved