OFFSET
1,4
FORMULA
EXAMPLE
a(5)=3; there are two partitions of 5 into two parts: (4,1) and (3,2). The sum of the smaller squarefree parts is 1+2=3. Thus a(5)=3.
a(6)=6; there are three partitions of 6 into two parts: (5,1), (4,2) and (3,3). All of the smaller parts are squarefree, so a(6) = 1+2+3 = 6.
MATHEMATICA
Table[Sum[i*MoebiusMu[i]^2, {i, Floor[n/2]}], {n, 70}]
PROG
(PARI) a(n) = sum(i=1, n\2, i * moebius(i)^2); \\ Michel Marcus, Oct 04 2015
(PARI) a(n)=my(s); forsquarefree(k=1, n\2, s += k[1]); s \\ Charles R Greathouse IV, Jan 08 2018
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Wesley Ivan Hurt, Oct 03 2015
STATUS
approved